Using properties of a series circuit, the sum of the voltages across the LED and resistor R must equal the supply voltage. \({V_s} = {V_{LED}} + {V_R}\) Now substitute the supply voltage (\(6V ...

And finally, in a parallel circuit, the total resistance of two resistors is less than the resistance of the smallest individual resistor. ELLIE: That feels like a bit of a tongue twister ...